| 修订版 | f8698468d2fb7956da8d5feba8a871b003ad0f2c (tree) |
|---|---|
| 时间 | 2010-09-10 19:24:05 |
| 作者 | lorenzo |
| Commiter | lorenzo |
I added another trivial function to find the [i[j]] entry of a list of lists.
haskell/simple_read.hs (diff)| @@ -49,6 +49,13 @@ | ||
| 49 | 49 | |
| 50 | 50 | print second_col |
| 51 | 51 | |
| 52 | + let my_el=find_ij trans 1 3 | |
| 53 | + | |
| 54 | + putStrLn "The element [1,3] (counted from zero!) in my list is, " | |
| 55 | + | |
| 56 | + print my_el | |
| 57 | + | |
| 58 | + | |
| 52 | 59 | |
| 53 | 60 | |
| 54 | 61 |
| @@ -57,3 +64,6 @@ | ||
| 57 | 64 | firstColumn xss = head (transpose xss) |
| 58 | 65 | |
| 59 | 66 | nthColumn xss n = (transpose xss) !! n -- my first haskell function! |
| 67 | + | |
| 68 | +find_ij xss i j = (xss !! i) !! j -- for the case of this function, each entry of a list of lists (i.e. each sublist) is meant to be | |
| 69 | + --a row. | |
| \ No newline at end of file |
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